36x^2+72x+29=0

Solution for 36x^2+72x+29=0 equation:

36x^2+72x+29=0

a = 36; b = 72; c = +29;
Δ = b2-4ac
Δ = 722-4·36·29
Δ = 1008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1008}=\sqrt{144*7}=\sqrt{144}*\sqrt{7}=12\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-12\sqrt{7}}{2*36}=\frac{-72-12\sqrt{7}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+12\sqrt{7}}{2*36}=\frac{-72+12\sqrt{7}}{72}
$